a rectangle with a perimeter of 32 inches has whole-number side lengths. what is the difference between the greatest and the least areas of the rectangle?
Accepted Solution
A:
Answer:49Step-by-step explanation:Let x represent the length and y represent the width of the given rectangle. The perimeter of the rectangle will be:Perimeter = 2(x + y)32 = 2(x + y)16= x + yThis means, the sum of length and width of the rectangle can be 16. Since only whole number side lengths are allowed, following are the possibilities:Side Lengths: 15, 1 Area = 15Side Lengths: 14, 2 Area = 28Side Lengths: 13, 3 Area = 39Side Lengths: 12, 4 Area = 48Side Lengths: 11, 5 Area = 55Side Lengths: 10, 6 Area = 60Side Lengths: 9, 7 Area = 63Side Lengths: 8, 8 Area = 64Hence the largest possible value of Area is 64 and the least possible value is 15. The difference is 64 - 15 = 49